How to find minimum value in an array using ternary operator in swift

Question

let array = [2,3,5,7,3,1,8,9,0,2,4,1]
var minvalue = array[0]
for values in array {
  values < minvalue ? minvalue = values : minvalue
}
print(minvalue)

This is the code i tried , I want the minimum value in the array, If I use if..else I can able to do but cant find using ternary operator.

Answer 1

You can use ternary operator this way.

for values in array {
    minvalue = values < minvalue ? values : minvalue
}

But in Swift instead of that simplest option is to use min() .

print(array.min())

Answer 2

获得最小值 SWIFT 3

array.min()

Answer 3

You can do this by sorting the array:

let sortedArray = array.sorted()
var minvalue = sortedArray[0]