What is the overhead of this operation to modify by reference in C++?

Question

Let's say there is a large vector called second , and now I want my own vector first to point to the large vector. I wrote this code:

#include <iostream>
#include <vector>

std::vector<int> second (100000,100);
void modify(std::vector<int>& i) {
  i = second;
}
int main ()
{
  std::vector<int> first(1, 1); 
  modify(first);    
  return 0;
}

Is it true that there is an overhead for modify function? Will the content of second to be cloned into a new array and then passed into first , or is it just passed by reference with negligible overhead?

Answer 1

Yes, this will copy the entire vector , and the complexity is linear in size of second , as stated in the ref .

What you did avoid by passing a reference as the function parameter is copying first into the parameter i . In other words, if your function was this (passing the vector by value-which would change the semantic of the function):

// more expensive!
void modify(std::vector<int> i) {
  i = second;
}

then you would pay the cost of copying first to i , plus the cost of copying second to i . Of course in your code, this would make no difference, since i is tiny, but in general it's a good practice to pass large objects by reference, in order to avoid unnecessary copies.

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Tip: Study move semantics.