I have a table with customer cards. A customer can have several cards. For every customer card there is one row. If a customer has several cards, there are several rows. There are two different card types A and B. For every card the last_used
date is stored.
I want to check if there are customers with both customer cards of type A and B, where the last_used date of card B is younger then the last_used date of card A.
This is my table CUSTOMER_CARDS.
card_id | customer_id | card_type | last_used
----------------------------------------------
1 | c1 | A | 2017-07-07
2 | c1 | B | 2016-04-01
3 | c2 | A | 2017-06-04
4 | c2 | B | 2017-07-03
5 | c3 | A | 2016-02-23
6 | c3 | B | 2017-04-17
I need a select statement which selects the customer_id
of customer c2
, who has a card of type B which is younger then his cards of type A. How do I achieve this?
You need Group By
and Having
clause
select customer_id
from yourtable
Group by customer_id
Having Min(case when card_type = 'B' then last_used end) > Max(case when card_type = 'A' then last_used end)
Can you try something like this?
SELECT A.card_id, A.customer_id, A.card_type, A.last_used
FROM CUSTOMER_CARDS A
INNER JOIN CUSTOMER_CARDS B ON A.customer_id=B.customer_id
WHERE A.card_type='B'
AND B.card_type='A' AND A.last_user > B.last_used
;
select d1.cusid,d1.cardtyp,d1.lstusd
from democat d1
join democat d2 on d1.cusid = d2.cusid
where d1.lstusd < d2.lstusd and d1.cardtyp = 'B'
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