Say I've got a column in my Pandas Dataframe that looks like this:
s = pd.Series(["ab-cd.", "abc", "abc-def/", "ab.cde", "abcd-"])
I would like to use this column for fuzzy matching and therefore I want to remove characters ('.' , '/' , '-') but only at the end of each string so it looks like this:
s = pd.Series(["ab-cd", "abc", "abc-def", "ab.cde", "abcd"])
So far I started out easy so instead of generating a list with characters I want removed I just repeated commands for different characters like:
if s.str[-1] == '.':
s.str[-1].replace('.', '')
But this simply produces an error. How do I get the result I want, that is strings without characters at the end (characters in the rest of the string need to be preserved)?
Replace with regex will help you get the output
s.replace(r'[./-]$','',regex=True)
or with the help of apply incase looking for an alternative
s.apply(lambda x :x[:-1] if x[-1] is '.' or '-' or '/' else x)
0 ab-cd 1 abc 2 abc-def 3 ab.cde 4 abcd dtype: object
You can use str.replace with a regex:
>>> s = pd.Series(["ab-cd.", "abc", "abc-def/", "ab.cde", "abcd-"])
>>> s.str.replace("\.$|/$|\-$","")
0 ab-cd
1 abc
2 abc-def
3 ab.cde
4 abcd
dtype: object
>>>
which can be reduced to this:
>>> s.str.replace("[./-]$","")
0 ab-cd
1 abc
2 abc-def
3 ab.cde
4 abcd
dtype: object
>>>
You can use str.replace
with a regular expression
s.str.replace(r'[./-]$','')
Substitute inside [./-]
any characters you want to replace. $
means the match should be at the end of the string.
To replace "in-place" use Series.replace
s.replace(r'[./-]$','', inplace=True, regex=True)
I was able to remove characters from the end of strings in a column in a pandas DataFrame with the following line of code:
s.replace(r'[./-]$','',regex=True)
Where all entries in between brackets ( [./-] ) indicate characters to be removed and $ indicate they should be removed from the end
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