So basically in my text file, the information is layed out like this
([x,x,x,x,x,x,x,x,x,x,,x],[x,x,x,x],[x,x,x])
how would i remove the brackets so that all of it becomes one array and i can just call it by position[0]
or position[10]
?
will it help ? Try out :
list2=r"([x,x,x,x,x,x,x,x,x,x,,x],[x,x,x,x],[x,x,x])"
old_list=[i for i in list2]
new_list=[i for i in old_list if i!=',' and i!='(' and i!=')' and i!='[' and i!=']']
print(new_list)
output:
['x', 'x', 'x', 'x', 'x', 'x', 'x', 'x', 'x', 'x', 'x', 'x', 'x', 'x', 'x', 'x', 'x', 'x']
Update soltion basis on your screenshot :
list_22=([1,2,3,4],["couple A","couple B","couple C"],["f","g","h"])
print([j for i in list_22 for j in i])
output:
[1, 2, 3, 4, 'couple A', 'couple B', 'couple C', 'f', 'g', 'h']
You can flatten the lists inside the tuple by looping over them like this.
tuple_of_lists = ([x,x,x,x,x,x,x,x,x,x,,x],[x,x,x,x],[x,x,x])
resulting_list = []
for lis in tuple_of_lists:
resulting_list.extend(lis)
I hope it helps.
Edited:- May be this function can help.
def formatter(string):
l = len(string)
to_avoid = {',', '[', ']', '(', ')', '"'}
lis = []
temp = ''
for i in range(l):
if string[i] in to_avoid:
if temp != '':
lis.append(temp)
temp = ''
continue
else:
temp += string[i]
return lis
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