Hi I am having trouble getting the time two hours ago in a similar function to my get_timestamp =>
def get_timestamp():
"""Return correctly formatted timestamp"""
return strftime("%Y-%m-%dT%H:%M:%SZ", gmtime())
def two_hours_ago():
"""Return correctly formatted timestamp"""
last = (date.today() - timedelta(hours=1))
return strftime("%Y-%m-%dT%H:%M:%SZ", gmtime()-'2HOURS')
I tried this:
def two_hours_ago():
"""Return correctly formatted timestamp"""
today = date.today()
yesterday = (today - timedelta(hours=2))
print(yesterday.timetuple())
return strftime("%Y-%m-%dT%H:%M:%SZ", yesterday.timetuple())
UPDATE thank you Huang Yen Hao
I was looking for a 2 hour interval returned in ISO format for Amazon MWS, I used the following functions to return the correctly formatted time.
def two_hours_ago():
"""Return correctly formatted timestamp"""
now = datetime.now()
two_hours_ago = (now - timedelta(hours=2))
return two_hours_ago.strftime("%Y-%m-%dT%H:%M:%SZ")
def now():
"""Return correctly formatted timestamp"""
now = datetime.now()
two_hours_ago = (now - timedelta(hours=0))
return two_hours_ago.strftime("%Y-%m-%dT%H:%M:%SZ")
I don't really understand the code that is today = date.today()
.
Is it means, for example, 2017/10/18 00:00:00?
The following code can get time two hours ago. I am not sure what you what is it or not..
from datetime import datetime, timedelta
def two_hours_ago():
"""Return correctly formatted timestamp"""
now = datetime.now()
two_hours_ago = (now - timedelta(hours=2))
return two_hours_ago.strftime("%Y-%m-%dT%H:%M:%SZ")
For this code, it will perform like following
>>> two_hours_ago()
'2017-10-19T11:28:40Z'
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