I have two html for left side image & content and for right side image & content. value print from models. what can i write in for-each loop to print odd and even value alternatively in partial view in page from Model.
@inherits UmbracoViewPage<List<ProjectName.Models.DealerSectionModel>> @using ProjectName.Models; @using Umbraco.Core; @{ foreach (DealerSectionModel historylist in Model) // what should i write in this loop .(ex if 1 value in model then print odd html) { if () { @RenderEvenHistoryList(historylist) } else { @RenderOddHistoryList(historylist) } } } @helper RenderOddHistoryList(DealerSectionModel item) { <div class="row history-second-section py-2 py-xl-4 py-lg-4 py-md-4 py-sm-2"> <div class="col-12 col-xl-6 col-lg-6 col-md-6 col-sm-12 history-second-images"> <div class="quote my-3"><iframe src="@item.VideoUrl" width="510" height="282" frameborder="0" allowfullscreen></iframe></div> </div> <div class="col-12 col-xl-6 col-lg-6 col-md-6 col-sm-12 history-second-content"> <div class="content-year">@item.Title </div> <h4>@item.ImageTitle</h4> <p>@item.ImageDescription</p> </div> </div> } } @helper RenderEvenHistoryList(DealerSectionModel item) { // render html for even model value } }
I don't know much about umbraco, but why not try something simple like
@{
var even = false;
foreach (DealerSectionModel historylist in Model) // what should i write in this loop .(ex if 1 value in model then print odd html)
{
if (even)
{
@RenderEvenHistoryList(historylist)
}
else
{
@RenderOddHistoryList(historylist)
}
even = !even;
}
}
You can do like this
@{ int count = 1;
foreach (DealerSectionModel historylist in Model)
{
if (count % 2 == 0)
{
@RenderEvenHistoryList(historylist)
}
else
{
@RenderOddHistoryList(historylist)
}
count++;
}
}
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