Display smallest even and odd number from six integers without using loops and arrays

Question

So I am trying to do an assignment for my class but for some reason I cant get the output to match with what I need. I have to make a program that asks for 6 integers and display the smallest even and odd. There will be 3 even entered and 3 odd but the order is unknown and we can't use loops or arrays. This sample is just what i have so far but I can't seem to understand why a and b won't work.

int a, b, c, d, e, f, smallEven=0, smallOdd=0;
cout<<"Enter a number:\n";
cin>>a;

if (a%2==0)
    smallEven=a;
else if (a%2==1)
    smallOdd=a;

cout<<"Enter a number:\n";
cin>>b;

if (b%2==0)
    if (smallEven=0)
        smallEven=b;
    else if (b<smallEven)
        smallEven=b;
else if (b%2==1)
    if (smallOdd=0)
        smallOdd=b;
    else if (b<smallOdd)
        smallOdd=b;

cout<<smallEven;
cout<<smallOdd;

Answer 1

The reason why this isn't doing what you're expecting is that you're using an assignment operator (=) instead of the comparison operator for equality (==) in two places:

if (b%2==0)
    if (smallEven=0)   // should be == here
        smallEven=b;
    else if (b<smallEven)
        smallEven=b;
else if (b%2==1)
    if (smallOdd=0)    // should be == here
        smallOdd=b;
    else if (b<smallOdd)
        smallOdd=b;