Printing lower case letters with corresponding ASCII code using a for loop

Question

So far this is what I have

System.out.println("problem 8");
int charletter = 0;
int charletter1 = 'a';
{
for (charletter = 'a'; charletter < 123; charletter++)
System.out.println(charletter);
System.out.println(charletter1);
}
}

The result is this list of according numbers without the letters as so:

Please enter the problem you want to solve:
8
problem 8
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
97

How do I make it so I can get az to show up next to or under their according number as well as getting rid of the 97 at the very end? Thanks everyone.

Answer 1

cast to char like so:

for (charletter = 'a'; charletter < 123; charletter++)
       System.out.println(charletter + "" + (char)charletter);

then get rid of System.out.println(charletter1); to avoid the 97 at the end.

Answer 2

To get rid of the 97, remove the second System.out.println . The for loop only operates on the first System.out.println . To get the answer you want, use this statement instead of the first System.out.println :

for(char charletter = 'a'; charletter <= 'z'; charletter++) {
    System.out.printf("%c %d%n", charletter, (int) charletter);
}