How to remove '\x' from list =[ '\xbb', '\x02', '\x00', '\x11', '\xbe']

Question

I have some data from Serial Port as follows

list_input =[ '\xbb', '\x02', '\x00', '\x11', '\xbe', '\x04', '\x00', '\x0', '\x08', '\x3', '\xb2', '\xdd', '\xd9', '\x01', '\x00', '\x00', '\x00', '\x00', '\xc4', '\x1e'] 

I want to remove '\\x' from each element and get output like,

list_output=[bb,02,00,22,be,04,00,08,dd]

if i do this list_input =''.join(map(str, list_input)) i get this output " " 4 3 @ " ie garbage value.

Please suggest any suitable solution.

Answer 1

The strings \\xbb , \\x02 ecc are single character strings. What you are seeing is the hex escape representation of them, since the ASCII character with code 2 is not a printable character.

It seems like you actually want the base-16 representation of the number represented by this characters, without the x prefix, hence you can us e ord to obtain the ASCII value and then hex to convert it into its hexadecimal representation:

>>> ord('\x02')
2
>>> ord('\xbb')
187
>>> hex(2)
'0x2'
>>> hex(187)
'0xbb'

If you don't want the 0x prefix oyu can just use slicing to remove that part:

result = [hex(ord(x))[2:] for x in list_input]