How can I take multiple inputs from the user?

Question

I'm trying to create a program where python will take multiple inputs to calculate the average of the input but it doesn't work though I search a lot but my problem differs from the rest as I use class. my code is as:

 class my_class(object):
        def __init__(self, number1, number2, number3):
            self.number1 = number1
            self.number2 = number2
            self.number3 = number3

        def defAvrg(self):  # get the defAvrg of three numbers
            return  (self.number1 + self.number2 + self.number3)/3
            #resulin = resulted / 3
            #return resulted
   my_class2 = my_class([float(input("Enter number %s: "%i)) for i in range(3)])
   print(my_class2.defAvrg())

Objective: I want to take three input to find the average.

Answer 1

The __init__() method for your class requires 3 positional parameters (in addition to self ) but your code passes only one - a list of the numbers entered by the user. You need to pass each of those numbers as a separate argument. You can use the * operator to unpack the items in the list and pass these as separate arguments:

my_class2 = my_class(*[float(input("Enter number %s: "%i)) for i in range(3)])

That will solve the immediate problem, however, it would be more flexible if your class accepted a list of the numbers, binding that to an attribute of the object. Your average method would then calculate the average using the list, or it could simply use statistics.mean() :

from statistics import mean

class my_class(object):
    def __init__(self, numbers):
        self.numbers = numbers

    def defAvrg(self):
        return mean(self.numbers)

The advantage of this approach is that you can collect an arbitrary number of values from the user.

Answer 2

You can call your Script with: scriptname n*<param^n> So for You it would be python script.py number1 number2 number3

You can access them in Python with sys.argv[1-3] , sys.argv[0] is always the Script Name

Answer 3

您将列表作为单个参数传递，您需要扩展列表，以解压缩列表，您可以使用*

myClass(*list())

Answer 4

Such a solution works for me.

numbers = list()
for i in range(0, 3):
    inputNr = int(input("Enter a number: "))
    if(inputNr == -99):
        break

    numbers.append(inputNr)

#Then we take all of the numbers and calculate the sum and avg on them
sum = 0
for j, val in enumerate(numbers):
    sum += val

print("The total sum is: " + str(sum))
print("The avg is: " + str(sum / len(numbers)))