How to remove all occurrences of any given character from string?

Question

My code:

    function removeFromString(mystring,char){

    let regex = new RegExp(char, 'g');
    let string;
    for(let i; i< mystring.length; i++){
        string = mystring.replace(regex, ''));

    }
    console.log(mystring);
}
removeFromString('Hello How are you','o');

This doesn't work. Any idea what am I doing wrong?

Answer 1

The method String.replace() doesn't change the string, it creates a new string. Return the result of the replace.

In addition, since you've used the g flag in the regex, it will replace all occurrences in the string, so you don't need the for loop.

 function removeFromString(mystring, char) { const regex = new RegExp(char, 'g'); return mystring.replace(regex, ''); } console.log(removeFromString('Hello How are you', 'o')); 

You can also achieve the same thing with a loop, by rebuilding the string from all characters in the original string the are not the char :

 function removeFromString(mystring, char) { let string = ''; for (let i = 0; i < mystring.length; i++) { if(mystring[i] !== char) string += mystring[i]; } return string; } console.log(removeFromString('Hello How are you', 'o')); 

Answer 2

You can simply use replace for it. No need for loop. like

 var str = "How are you?"; console.log(str.replace(/o/g, "")) 

g flag is to replace all occurrences

Or Just for fun.

 var str = "How are you?"; console.log(str.split("o").join('')) 

split string by your desired character. This will give you an array. Now you can join this array with ''