String Huge Decimal Numbers In Java

Question

double a=816992306.6297043221;
System.out.println("a="+a);

The problem with this is that the number is too large for double, and it gives the following output:

a=8.169923062970433E7

When I decrease the number, the result gets displayed correctly. What is the efficient solution for this problem?

Answer 1

You can use a BigDecimal number instead of double :

Immutable, arbitrary-precision signed decimal numbers.

BigDecimal can represent any number with the choosen precision .

Double has limits on maximum and minimum values and on precision .

Answer 2

I think it is a precision problem.

https://docs.oracle.com/javase/1.5.0/docs/api/java/util/Formatter.html#syntax

You can check this link out for learning about format.

You can use DecimalFormat Class

double d1 = 3.14159;
double d2 = 1.235;

DecimalFormat format = new DecimalFormat("#.##");

double roundedD1 = format.format(d1); // 3.14
double roundedD2 = format.format(d2); // 1.24

If you want to set the precision during runtime.

format.setMaximumFractionDigits(precision);