turn each element in list to key value pairs

Question

I have two lists

list1 = [1,a,2,b,3,c]
list2 = [5,d,6,e,7,f]

I tried to use list(zip(list1, list2))

Then is what I got:

[(1, 5), ('a', 'd'), (2, 6), ('b', 'e'), (3, 7), ('c', 'f')]

I want something like this to be my output:

{1:a, 5:d, 2:b, 6:e, 3:c,7:f}

Any help is appreciated.

Answer 1

Via iter and zip :

>>> it = iter(list1 + list2)
>>> dict(zip(it,it))
{1: 'a', 2: 'b', 3: 'c', 5: 'd', 6: 'e', 7: 'f'}

Answer 2

I'd first add your two lists together

>>> values = list1 + list2
>>> values
[1, 'a', 2, 'b', 3, 'c', 5, 'd', 6, 'e', 7, 'f']

Then use a dict comprehension to stride through the list by every other element, and zip that against the same stride but offset by one.

>>> {key:value for key,value in zip(values[::2], values[1::2])}
{1: 'a', 2: 'b', 3: 'c', 5: 'd', 6: 'e', 7: 'f'}