Looking for data splitter line by line, by using python
As example file "file" contain:
X
X
Y
Z
Z
Z
I need the clean way to split this file into 3 different ones, based on letter
As a sample:
def split_by_platform(FILE_NAME):
with open(FILE_NAME, "r+") as infile:
Data = infile.read()
If the file contains "X"
write to x.txt
If the file contains "Y"
write to y.txt
If the file contains "Z"
write to z.txt
x.txt file will look like:
X
X
y.txt file will look like:
Y
z.txt file will look like:
Z
Z
Z
EDIT thanks to @bruno desthuilliers, who reminded me of the correct way to go here:
Iterate over the file object (not 'readlines'):
def split_by_platform(FILE_NAME, out1, out2, out3):
with open(FILE_NAME, "r") as infile, open(out1, 'a') as of1, open(out2, 'a') as of2, open(out3, 'a') as of3:
for line in infile:
if "X" in line:
of1.write(line)
elif "Y" in line:
of2.write(line)
elif "Z" in line:
of3.write(line)
EDIT on a hint of @dim: Here the more general approach for an arbitrary length list of flag chars:
def loop(infilename, flag_chars):
with open(infilename, 'r') as infile:
for line in infile:
for c in flag_chars:
if c in line:
with open(c+'.txt', 'a') as outfile:
outfile.write(line)
This should do it:
with open('my_text_file.txt') as infile, open('x.txt', 'w') as x, open('y.txt', 'w') as y, open('z.txt', 'w') as z:
for line in infile:
if line.startswith('X'):
x.write(line)
elif line.startswith('Y'):
y.write(line)
elif line.startswith('Z'):
z.write(line)
Here is a more generic way to do the same job:
from collections import Counter
with open("file.txt", "r+") as file:
data = file.read().splitlines()
counter = Counter(data)
array2d = [[key, ] * value for key, value in counter.items()]
print array2d # [['Y'], ['X', 'X'], ['Z', 'Z', 'Z']]
for el in array2d:
with open(str(el[0]) + ".txt", "w") as f:
[f.write(e + "\n") for e in el]
The above code will generate X.txt
, Y.txt
and Z.txt
with the corresponding values. If you have for example several C
letters the code will generate a file C.txt
.
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