Python logic if and or opposite

Question

Level = 4
Name = "Mike"
Form = None
if Level == 5 or Name in ['James','Chris','Alex'] or (Name in ['John','Mike'] and Form):

The above code does exactly what I want it to do, but I can't figure out how to do the opposite:

eg

if Level != 5 and Name not in ['James','Chris','Alex'] and (Name not in ['John','Mike'] and Form):

As close as I got but does not work the same.

Answer 1

How about clubbing everything in parenthesis and just use not in the beginning. That way, you don't need to reverse any operator.

if not (Level == 5 or Name in ['James','Chris','Alex'] or (Name in ['John','Mike'] and Form)):

Answer 2

Your question is a bit vague, As far as i understand it should be pretty simple,

if not (Level == 5 or Name in ['James','Chris','Alex'] or (Name in ['John','Mike'] and Form)):

another easy way would be to do something like this

if Level == 5 or Name in ['James','Chris','Alex'] or (Name in ['John','Mike'] and Form):
    pass
else:
    # your code here