Is it possible to convert
[[35, "Bill"], [20, "Nancy"], [27, "Joan"]]
to
{"Bill": 35, "Nancy": 20, "Joan": 27}
using the .map()
or .reduce()
methods?
I can convert the array using:
const arr = [[35, "Bill"], [20, "Nancy"], [27, "Joan"]]; let obj = {}; for (let item of arr) { obj[item[1]] = item[0]; } console.log(obj);
But my attempts to do this using map
or reduce
are failing. Any ideas?
If supported, you can use Object.fromEntries()
to convert an array of [key, value]
pairs to an object. In this case, the pairs are [value, key]
, so we'll need to map them first to an array of [key, value]
pairs.
const arr = [[35, "Bill"], [20, "Nancy"], [27, "Joan"]]; const obj = Object.fromEntries(arr.map(([v, k]) => [k, v])); console.log(obj);
Use Array.map()
to create an array of objects where each contains a single key/value. Combine them to a single object by spreading into Object.assign()
:
const arr = [[35, "Bill"], [20, "Nancy"], [27, "Joan"]]; const obj = Object.assign(...arr.map(([v, k]) => ({ [k]: v }))); console.log(obj);
If you need to use the object as a dictionary, a better solution would be to convert the array of tuples to a Map :
const arr = [[35, "Bill"], [20, "Nancy"], [27, "Joan"]]; const map = new Map(arr.map(([v, k]) => [k, v])); console.log(map.get('Bill'));
Yes, you can use reduce
- on each iteration, extract both items from the array (as the key and the value), assign the value to the appropriate key in the accumulator, and return the accumulator:
const input = [[35, "Bill"], [20, "Nancy"], [27, "Joan"]]; const obj = input.reduce((a, [val, key]) => { a[key] = val; return a; }, {}); console.log(obj);
You could map the items for new objects and assign all to a single object with Object.assign
.
var array = [[35, "Bill"], [20, "Nancy"], [27, "Joan"]], object = Object.assign(...array.map(([v, k]) => ({ [k]: v }))); console.log(object);
You can use reduce
with Object.assign
:
let array = [[35, "Bill"], [20, "Nancy"], [27, "Joan"]]; let result = array.reduce((acc, [value, key]) => Object.assign(acc, { [key]: value }), {}); console.log(result);
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