I'm new to Python and I am trying to generate a list of 4 random numbers with integers between 1 and 9. The list must contain no repeating integers.
The issue I am having is that the program doesn't output exactly 4 numbers everytime. Sometimes it generates 3 numbers or 2 numbers and I can't figure out how to fix it.
My code:
import random
lst = []
for i in range(5):
r = random.randint(1,9)
if r not in lst: lst.append(r)
print(lst)
Is there a way to do it without the random.sample? This code is part of a larger assignment for school and my teacher doesn't want us using the random.sample or random.shuffle functions.
Your code generates 5 random numbers, but they are not necessarily unique. If a 2
is generated and you already have 2
in list
you don't append it, while you should really be generating an alternative digit that hasn't been used yet.
You could use a while
loop to test if you already have enough numbers:
result = [] # best not to use list as a variable name!
while len(result) < 5:
digit = random.randint(1, 9)
if digit not in result:
result.append(digit)
but that's all more work than really needed, and could in theory take forever (as millions of repeats of the same 4 initial numbers is still considered random). The standard library has a better method for just this task.
Instead, you can use random.sample()
to take 5 unique numbers from a range()
object:
result = random.sample(range(1, 10), 5)
This is guaranteed to produce 5 values taken from the range, without duplicate digits, and it does so in 5 steps.
Use random.sample
:
import random
random.sample(range(1, 10), 4)
This generates a list of four random values between 1
to 9
with no duplicates.
Your issue is, you're iterating 5 times, with a random range of 1-9. That means you have somewhere in the neighborhood of a 50/50 chance of getting a repeat integer, which your conditional prevents from being appended to your list.
This will serve you better:
def newRunLst():
lst = []
while len(lst) < 4:
r = random.randint(1,9)
if r not in lst: lst.append(r)
print lst
if random list needed is not too small (compared to the total list) then can
(pd.DataFrame([(i,np.random.rand()) for i in range(10)]).sort_values(by=1))[0][:5].sort_index()
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