I had successfully counted the number of vowels in each element of string array. But i am unable to compare them and the print the array element which has the least number of vowels. Please help me out. This is the code i had written so far....
public static void main(String[] args) {
Scanner s = new Scanner(System.in);
int N = s.nextInt();
int vowelcount = 0;
int maxcount = 0, sum = 0;
String a[] = new String[N];
for(int i = 0; i < N; i++) {
a[i] = s.next();
}
for(int i = 0; i < N; i++) {
String str = a[i];
for(int j = 0; j < str.length(); j++) {
if(str.charAt(j) == 'a' || str.charAt(j) == 'e' || str.charAt(j) == 'i'
|| str.charAt(j) == 'o' || str.charAt(j) == 'u') {
vowelcount = vowelcount + 1;
}
}
System.out.println(vowelcount);
vowelcount = 0;
}
}
I have modified your code.. Please try running the below code
public static void main(String[] args) {
Scanner s=new Scanner(System.in);
int N=s.nextInt();
int vowelcount=0;
int maxcount=0,sum=0;
String a[]=new String[N];
for(int i=0;i<N;i++){
a[i]=s.next();
}
//added
int minCount = Integer.MAX_VALUE;
int minCountIndex = Integer.MAX_VALUE;
//till here
for(int i=0;i<N;i++){
String str=a[i];
for(int j=0;j<str.length();j++){
if(str.charAt(j)=='a'||str.charAt(j)=='e'||str.charAt(j)=='i'||str.charAt(j)=='o'||str.charAt(j)=='u'){
vowelcount=vowelcount+1;
}
} //Add below lines
if(vowelcount < minCount) {
minCount = vovelcount;
minCountIndex = i;
} //till here
System.out.println(vowelcount);
vowelcount=0;
}
System.out.println("String with Minimum Vovels :" + a[minCountIndex]); // Added this
}
Create a custom comperator class which suits your needs like this:
static class SortDescendingByNumberOfVowels implements Comparator<String> {
private int getNumberOfVowels(String str) {
int counter = 0;
for(int i = 0; i < str.length(); i++) {
if(str.charAt(i) == 'a' || str.charAt(i) == 'e' || str.charAt(i) == 'i'
|| str.charAt(i) == 'o' || str.charAt(i) == 'u') {
counter += 1;
}
}
return counter;
}
@Override
public int compare(String str1, String str2) {
return getNumberOfVowels(str2) - getNumberOfVowels(str1);
}
}
Then use the above comperator to sort the array by using another signature of Arrays.sort()
which takes as a 2nd parameter the comperator:
public static void main(String[] args) {
Scanner s = new Scanner(System.in);
int N = Integer.parseInt(s.nextLine());
String a[] = new String[N];
for(int i = 0; i < N; i++) {
a[i] = s.nextLine();
}
System.out.println("Initial array: " + Arrays.toString(a));
Arrays.sort(a, new SortDescendingByNumberOfVowels());
System.out.println("Sorted array : " + Arrays.toString(a));
System.out.println("Item with less vowels: " + a[N - 1]);
}
You could use a regex rather than comparing individual characters to get the vowel count
Pattern vowels = Pattern.compile("[aeiou]", Pattern.CASE_INSENSITIVE);
int numberOfVowels = value.length() - vowels.matcher(value).replaceAll("").length();
You could also use a stream to do the sorting.
Pair fewest = Arrays.stream(values)
.map(value -> new Pair(value.length() - vowels.matcher(value).replaceAll("").length(), value))
.sorted((v1, v2) -> Integer.compare(v1.length, v2.length))
.findFirst().orElse(null);
System.out.println(fewest.value);
That relies on having a Pair class which holds the length and value
private class Pair {
int length;
String value;
Pair(int length, String value) {
this.length = length;
this.value = value;
}
}
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