how to get specific int value from string in java [122356]

Question

How to get all int value from a string value, eg [122356]. I tried this:

Query query=s.createQuery("select pid from Patient where emailid=? ");

String pid = query.setParameter(0, email).list().toString();
char abc= pid.charAt(1);
int patientid=Character.getNumericValue(abc);

Answer 1

You can get an int value from a string value by using parseInt, like so:

int num = Integer.parseInt(string_of_number);

You should validate the value that num has after this operation. You can read about it here: parseInt

Answer 2

You could simply do :

int num = Integer.parseInt("[122356]".replaceAll("[\\[\\]]", ""));

Here we first replace all occurences of [ and ] with empty space and then parse the string.

Answer 3

list() might return more than one record,you need to get the specify record,and it better to use Integer.parseInt() get int value

Query query=s.createQuery("select pid from Patient where emailid=? ");

//get value from the first record
String pid = query.setParameter(0, email).list().get(0).toString();
char abc= pid.charAt(1);
int patientid=Character.getNumericValue(abc);
//better to use this get int
//int patientid=Integer.parseInt(abc);

Answer 4

将String解析回Integer；

int num = Integer.parseInt("122356");

Answer 5

In case you know that the String representation of your number is enclosed in brackets, then you have to remove them before parsing. You can do it like this:

// replace brackets with an empty String, needs two operations due to two different brackets
String numberInBrackets = "[123456]";
String numberWithoutBrackets = numberInBrackets.replace("[", "");
String numberWithoutBrackets = numberWithoutBrackets.replace("]", "");
int number = Integer.parseInt(numberWithoutBrackets);

Alternatively, you cut them off using String.substring(int beginIndex, int endIndex) :

// cut off the trailing and leading characters of the String
String numberInBrackets = "[123456]";
String numberWithoutBrackets = numberInBrackets.substring(1, numberInBrackets.length() - 1);

If the String just contains cyphers, then just do

String number = "123456";
int number = Integer.parseInt(number);

Answer 6

至少有3种方法（其中一种是Nicolas K.指出的），至少对我来说，这是最合适的方法，但是您也可以使用类似的方法（假设字符串位于[int]模式中） 。

 int number = Integer.parseInt(yourData.substring (1, yourData.lastIndexOf(']')));

Answer 7

you can use this for cut "[" and "]".

Thank you .

Query q = s.createQuery(" select profileid from Userprofile where emailid=?");

    String profileid = q.setParameter(0, email).list().toString();
    int start = 0; // '(' position in string
    int end = 0; // ')' position in string
    for (int i = 0; i < profileid.length(); i++) {
        if (profileid.charAt(i) == '[') // Looking for '(' position in string
        {
            start = i;
        } else if (profileid.charAt(i) == ']') // Looking for ')' position in  string
        {
            end = i;
        }
    }
    String number = profileid.substring(start + 1, end);

    int pkst = Integer.parseInt(number);
    System.out.println("your number is :" + number);