简体   繁体   中英

How to update a table joined with another table multiple times in Oracle?

I have three fields in my table and I want to update them by joining three times to another table. I know that I have to use merge into , but I couldn't find any similar query that uses merge into and join with only one table for multiple times.

The select statement is something like this:

select * from TABLE t
inner join DESTINATION_TABLE d1
on t.CODE1 = d1.CODE
inner join DESTINATION_TABLE d2
on t.CODE2 = d2.CODE
inner join DESTINATION_TABLE d3
on t.CODE3 = d3.CODE

Now how can I update three fields ( FIELD1 , FIELD2 , FIELD3 ) from TABLE by using fields from d1 , d2 , and d3 using merge into ?

EDIT:

The original query is:

select * from TOTAL
inner join GROUP_LEVEL_DETAIL gl1
on gl1.NAME = substr(GL, 1, instr(GL, ' -', 1))
inner join GROUP_LEVEL_DETAIL gl2
on GL2.NAME = replace(substr(GL, instr(GL, ' -', 1, 1), instr(GL, ' -', 1, 2) - instr(GL, ' -', 1, 1)), ' - ', '')
inner join GROUP_LEVEL_DETAIL gl3
on gl3.NAME = replace(substr(GL, instr(GL, '-', 1, 2), 500), '- ', '')

The sample data for TOTAL is:

  ID                GL                GL1_CODE   GL2_CODE   GL3_CODE
-----  ----------------------------- ---------- ---------- -----------
  1     Sample1 - Sample2 - Sample3    null        null       null
  2     John - Jack - Harry            null        null       null

The sample data for GROUP_LEVEL_DETAIL is:

  CODE         NAME        LEVEL_NO
---------  -----------   ------------
  SMP1       Sample1           1
  SMP2       Sample2           2
  SMP3       Sample3           3
  JCK1       Jack              1
  JHN2       John              2
  HRY3       Harry             3

And I want my TOTAL table get like this after the update:

  ID                GL                GL1_CODE   GL2_CODE   GL3_CODE
-----  ----------------------------- ---------- ---------- -----------
  1     Sample1 - Sample2 - Sample3    SMP1        SMP2       SMP3
  2     John - Jack - Harry            JCK1        JHN2       HRY3

From your revised question, I think the solution is to assemble the GROUP_LEVEL_DETAIL names in the subquery to make a key which you can join to the TOTAL table.

merge into TOTAL t
using ( select d1.code as d1_code
               , d2.code as d2_code
               , d3.code as d3_code
               , d1.name || ' - ' ||
                 d2.name || ' - ' ||
                 d3.name as joined_code
         from  GROUP_LEVEL_DETAIL d1
         cross join GROUP_LEVEL_DETAIL d2
         cross join GROUP_LEVEL_DETAIL d3
         where d1.level_no = 1
         and   d2.level_no = 2
         and   d3.level_no = 3  
       ) d
on ( t.gl = d.joined_code )
when matched then
    update 
    set t.gl_code1 = d.d1_code
        ,  t.gl_code2 = d.d2_code
        ,  t.gl_code3 = d.d3_code

The USING subquery generates a result set of all possible permutations of records from GROUP_LEVEL_DETAIL. After your revision I have included a WHERE clause to enforce the implied rule GL = 'level 1 - level 2 - level 3' . You may wish to not do that (perhaps not every record in TOTAL has a valid GL) or extend the WHERE clause to apply any other rules regarding valid combinations.

When the joins are based on primary keys or unique index you should be able to do the following:

--create tables and unix index
create table table1 (code number, field1 number, field2 number, field3 number);
create unique index table1_code_inx on table1 (code);

create table table2 (code number, field1 number, field2 number, field3 number);
create unique index table2_code_inx on table2 (code);

-- update data from table2 to table1
update( select a.FIELD1 A_FIELD1, a.FIELD2 A_FILED2, a.FIELD3 A_FIELD3,
               b.FIELD1 B_FIELD1, b.FIELD2 B_FILED2, b.FIELD3 B_FIELD3 
          from TABLE1 a, TABLE2 b
          where a.CODE = b.CODE )
set A_FIELD1 = B_FIELD1,
    A_FILED2 = B_FILED2,
    A_FIELD3 = B_FIELD3;

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM