I have the below function to find the string contains numbers and special characters, but it was not working
let validateStr = (stringToValidate) => {
var pattern = /^[a-zA-Z]*$/;
if (stringToValidate&& stringToValidate.length > 2 && pattern.test(stringToValidate))
{
return false;
} else {
return true;
}
};
validateStr("123$%^$") // I need the above function should return false.
validateStr("sdsdsdsd$%^$") // true
validateStr("sdsdsdsd") // true
validateStr("sdsdsdsd45678") // false
validateStr("$#*()%^$")//false
validateStr("123434333")//false
Your RegEx should be:
/[a-zA-Z]+[(@!#\$%\^\&*\)\(+=._-]{1,}/
Try the following way:
let validateStr = (stringToValidate) => { var pattern = /[a-zA-Z]+[(@!#\\$%\\^\\&*\\)\\(+=._-]{1,}/; if ( stringToValidate && stringToValidate.length > 2 && pattern.test(stringToValidate)) { return true; } else { return false; } }; console.log(validateStr("123$%^$")); //false console.log(validateStr("sdsdsdsd$%^$")); //true console.log(validateStr("sdsdsdsd45678"));//false console.log(validateStr("$#*()%^$")); //false console.log(validateStr("123434333")); //false
You can use this code to track number and special characters in your string value.
function checkNumberOrSpecialCharacters(stringValue){
if( /[^a-zA-Z\-\/]/.test( stringValue) ) {
alert('Input is not alphabetic');
return false;
}
alert('Input is alphabetic');
return true;
}
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