Regex can't getting the blank spaces and I can't split the string correctly?

Question

I'm creating a Regex in Python where I need to find a blank spaces in a string

Example

000#0123456789#ASimpleName#123456 000#987654321#OtherSimpleName#8765432
000#0123456789#ASimpleName#EUA 000#987654321#OtherSimpleName#8765432

In this case, if I use re.split('\\s' ) I solve my problem, but I can find this

000#0123456789#A simple Name#123456 000#987654321#Other Simple Name#8765432
000#0123456789#ASimpleName#EUA 000#987654321#OtherSimpleName#8765432

I've tried to use this expression [\\d|\\w]\\s\\d , but the Regex get 6 0 and A 0 , but I need only the blank space.

Answer 1

You may use the following regex with re.split :

\s+(?=000#)

Or, if there may be any 3 digits:

\s+(?=\d{3}#)

See the regex demo and the https://jex.im/regulex diagrams:

Details

• \\s+ - matches and consumes 1 or more whitespace chars
• (?=\\d{3}#) - makes sure that, immediately to the right of the current location, there are 3 digits followed with # . (?=000#) returns true only if the three digits are zeros. # may not be necessary here, but that depends on the actual data and requirements.