argument of type “int” incompatible with parameter of type “int*”

Question

The goal is to search the array and find a specific number in it and return the position. I have the method for how to do it down but trying to get it to run in the main method is giving me the error in the title. What do i do to fix?

#include "stdafx.h"
#include <iostream>
using namespace std;

int searchArray(int a[], int x) {
    for (int i = 0; i < a[100]; i++) {
        if (x == a[i])
            return i + 1;
        break;
    }
    return -1;
}

int main()
{
    int wait, x, y, a[100];

    //problem 3
    cout << "Enter the size of the array(1-100): ";
    cin >> y;

    for (int i = 0; i < y; i++) {
        cout << "Enter an array of numbers:";
        cin >> a[i];
    }
    searchArray(a[100], x); //i get error on this line with a[100]

    cin >> wait;

    return 0;
}

Expected is it should run with no errors and find position of a number in the array but I just get the error and cant run it.

Answer 1

After the for() loop in main(), you need something like:

cout << "Enter the value to search for: ";
cin >> x; 

wait = searchArray(a, x);

cout << x;
cout << " is at position: ";
cout << wait;

Answer 2

int searchArray(int a[], int x) 
{
    for (int i = 0; i < 100; i++) //change a[100] to 100 because it only needs the size not the array itself
    {
        if (x == a[i])
            return i + 1;
        break;
    }
    return -1;
}

int main()
{
    int wait, x, y, a[100];

    cout << "Enter the size of the array(1-100): ";
    cin >> y;

    for (int i = 0; i < y; i++) {
        cout << "Enter an array of numbers:";
        cin >> a[i];
    }

    cout<<"Number to look for: "; //sets a value for x
    cin>>x;

    cout<<"Index: "<<searchArray(a, x)<<endl; //function returns an int therefore a cout is needed

    cin >> wait;

    return 0;
}