Create a class that asks the user for a number, and then print out the following pattern based on the int input.
So the code I made result looked like this ...
12345
1234
123
12
But it should look like this
5
45
345
2345
12345
Scanner tri = new Scanner(System.in);
System.out.println("Enter a postive integer.");
int shape = tri.nextInt();
for(int c = shape; c > 1; --c){
for (int a = 1; a <= shape-c; a++){
System.out.print(" ");
}
for(int d = 1; d <= c; d++){
System.out.print(d);
}
System.out.println(" ");
Could you try this code below?
Scanner tri = new Scanner(System.in);
System.out.println("Enter a postive integer.");
int shape = tri.nextInt();
for (int c = shape; c >= 1; --c) {
for (int a = 1; a <= c; a++) {
System.out.print(" ");
}
for (int d = c; d <= shape; d++) {
System.out.print(d);
}
System.out.println(" ");
}
// result
// 5
// 45
// 345
// 2345
// 12345
Instead of using a nested loop, you can use some padding. Basically you need to have a string which consists of only spaces and is as long as the number of digits in your number.
In a loop take the substring of your number and fill the remaining with spaces. My code:
public static void pattern(int number)
{
String s=Integer.toString(number);
String padding="";
for(int i=0;i<s.length();i++,padding+=" ");
for(int i=1;i<=s.length();i++)
{
System.out.println(padding.substring(i)+s.substring(s.length()-i));
}
}
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