I have an ID list
id = [339, 344, 340, 343, 345, 342, 341]
already select as in the way in this link here , this is the code
mycursor.execute("SELECT * FROM news_tb where id IN ({})".format(",".join([str(i) for i in hasil])))
but the results are in sequence
[(339, '..'), (340, '..'), (341, '..'), (342, '..'), (343, '..'), (344, '..'), (345, '..')]
I want the data output to be sequential according to the id in the list. Thankyou
结果 = 排序(结果,键 = lambda x: id.index(x[0]))
Assuming your results are in results
,
r_dict = dict([r[0],r[1:]] for r in results)
ordered_results = [tuple([i]+list(r_dict[i])) for i in id]
print(ordered_results)
will print the desired list.
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