Change value of uneven to specific even numbers

Question

I have a dataframe with mixed data types and I would like to change the values of str cells (each consisting of two letters plus three numbers) so that uneven number become even numbers but the number decreases. AB123 should become AB122 while not changing the letter before it.

Here is an example dataframe with mixed types:

df = pd.DataFrame({'Opportunity':['AB122','AB123','AB125', 'AB124'],
           'Quantity': [2, 3, 4, 1],
           'Member': ["AACC", "AACC", "AACC", 'DDEE']})


print (df)
  Opportunity  Quantity Member
0       AB122         2   AACC
1       AB123         3   AACC
2       AB121         4   AACC
3       AB120         1   DDEE

I would like the outcome to be:

print (df2)

  Opportunity  Quantity Member
0       AB122         2   AACC
1       AB122         3   AACC
2       AB120         4   AACC
3       AB120         1   DDEE

Answer 1

Try:

df['Opportunity'] = df['Opportunity'].str[:2] + np.where(df['Opportunity'].str[2:].astype(int) % 2, df['Opportunity'].str[2:].astype(int).sub(1).astype(str), df['Opportunity'].str[2:])

And now:

print(df)

Is:

  Member Opportunity  Quantity
0   AACC       AB122         2
1   AACC       AB122         3
2   AACC       AB120         4
3   DDEE       AB120         1

Answer 2

Here's one way slicing with pandas's str accessor, subtracting the mod by 2 to the integer part and concatenating back to the column using str.cat :

d = df.Opportunity.str[-2:].astype(int)
df['Opportunity'] = df.Opportunity.str[:3].str.cat(d.sub(d.mod(2)).astype(str))

    Opportunity  Quantity Member
0       AB122         2   AACC
1       AB122         3   AACC
2       AB120         4   AACC
3       AB120         1   DDEE

---

Input dataframe:

print(df)

Opportunity  Quantity Member
0       AB122         2   AACC
1       AB123         3   AACC
2       AB121         4   AACC
3       AB120         1   DDEE

Answer 3

df['Opportunity'] = df.Opportunity.apply(lambda x: x[:-3]+str(int(x[-3:]) - 1) if int(x[-3:]) % 2 != 0 else x)

---

Opportunity  Quantity Member
0       AB122         2   AACC
1       AB122         3   AACC
2       AB120         4   AACC
3       AB120         1   DDEE

Answer 4

df = pd.DataFrame({'Opportunity':['AB122','AB123','AB125', 'AB124'],
               'Quantity': [2, 3, 4, 1],
               'Member': ["AACC", "AACC", "AACC", 'DDEE']})

even = lambda x: int(x) % 2 == 0
df['Opportunity'] = df['Opportunity'].apply(lambda x: x[:2] + (x[2:] if even(x[2:]) else str(int(x[2:]) -1)))

print(df)

output:

  Opportunity  Quantity Member
0       AB122         2   AACC
1       AB122         3   AACC
2       AB124         4   AACC
3       AB124         1   DDEE