I have a multi-line string and some empty lines between other lines. It looks like:
def msg = """
AAAAAA
BBBBBB
CCCCCC
DDDDDD
EEEEEE
TEST
FFFFF
GGGGGG
"""
I tried some regex expression with :
msg = msg.replaceAll('(\n\\\\s+\n)+', '')
Or
msg = msg.replaceAll('(\r?\n){2,}', '$1');
But nothing is good about what I'm looking...
Is it possible to remove only empty lines? to get something like that :
def msg = """
AAAAAA
BBBBBB
CCCCCC
DDDDDD
EEEEEE
TEST
FFFFF
GGGGGG
"""
Use regex (?m)^[ \\t]*\\r?\\n"
to remove empty lines:
log.info msg.replaceAll("(?m)^[ \t]*\r?\n", "");
To remain only 1 line use [\\\\\\r\\\\\\n]+
:
log.info text.replaceAll("[\\\r\\\n]+", "");
If you want to use the value later, then assign it
text = text.replaceAll("[\\\r\\\n]+", "");
Your current attempt seems very much on the right track, and I think the logic you want is to replace two or more newlines with just a single newline:
output = msg.replaceAll("(\r?\n)(?:\r?\n){1,}", "$1");
The trick here, to capture the actual newline type being used ( \\n
for Linux or \\r\\n
for Windows), is to capture a single \\r?\\n
first, followed then by at least one more newline.
Groovy golf!
msg.split('\n')
.findAll { it.trim() }
.join('\n')
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