Using an or statement in a conditional list comprehension to filter columns in a dataframe

Question

I'm trying to filter my columns in dataframe that contain the letters "R" or "H".

The code works when I only search for 1 of the letters but it's returning all the columns when I add an or statement.

I was wondering if it was possible to use the or in a list comprehension. Here is my code:

data = pd.read_csv(filename)
data_sorted = data.sort_values('Timestamp', ascending=False)
four_dec_cols = [col for col in data_sorted if 'H' in col]

failed code:

four_dec_cols = [col for col in data_sorted if 'RB' or 'H' in col]

Utlimately, I want to round the columns that contain 'H' or 'R' to 4 decimal places and all the rest to 2 decimal places so if theres maybe a more direct way to do that, i'd appreciate the suggestion.

Thanks so much!

Edit: So ideally - i'd like to return this dataframe with any column that contins RB or H rounded to 4 decimal places and everything else rounded to 2.

Answer 1

怎么样：

cols = df.columns[df.columns.str.contains('RB|H')]

Answer 2

Your current code checks whether 'RB' is true (existent) and hence returns all columns. Try:

four_dec_cols = [col for col in data_sorted if 'RB' in col or 'H' in col]