How do I extract strings with three forward slashes?

Question

I want to print out the items with three forward slashes as in my desired output.

Everything I try to find is extracting the data in between the slashes or just finding the ones with a slash.

data = ['int', '3/1/2/8', '4/2/1', '5/6/9/2',
    '4/1', '9/2/1', '1/4/8/6', 'prod', ]
for info in data:
    if '%d/%d/%d/%d' in info:
        print(info)

Desired outcome:

 3/1/2/8
 5/6/9/2
 1/4/8/6

Answer 1

A regular expression can help:

import re

out=[]
data=['int', '3/1/2/8', '4/2/1', '5/6/9/2','4/1', '9/2/1', '1/4/8/6', 'prod' ]

for i in data:
    if(re.match(".*/.*/.*/.*",i)):
        out.append(i)

print(out)

Output from this:

['3/1/2/8', '5/6/9/2', '1/4/8/6']

Answer 2

Use .count() as follows:

data = ['int', '3/1/2/8', '4/2/1', '5/6/9/2',
    '4/1', '9/2/1', '1/4/8/6', 'prod', ]
for info in data:
    if info.count('/') == 3:
        print(info)

Answer 3

You have just to make a function that checks if there is 4 /

for i in data:
    if len(i.split("/")) == 4:
        print(i)

Answer 4

data = ['int', '3/1/2/8', '4/2/1', '5/6/9/2', '4/1', '9/2/1', '1/4/8/6', 'prod', ] for info in data: if info.count('/') == 3: print(info)