Get the last part of a string in a list

Question

I have a list which contains the following string element.

myList = ['120$My life cycle 3$121$My daily routine 2']

I perform a .split("$") operation and get the following new list.

templist = str(myList).split("$")

I want to be able to store all the integer values from this templist which are at even indexes after the split.I want to return a list of integers.

Expected output: [120, 121]

Answer 1

You can split at $ and use a list comprehension with str.isdigit() to extract numbers:

mylist = ['120$My life cycle$121$My daily routine','some$222$othr$text$42']

# split each thing in mylist at $, for each split-result, keep only those that
# contain only numbers and convert them to integer
splitted = [[int(i) for i in p.split("$") if i.isdigit()] for p in mylist] 

print(splitted) # [[120, 121], [222, 42]]

This will produce a list of lists and convert the "string" numbers into integers. it only works for positive numbers-strings without sign - with sign you can exchange isdigit() for another function:

def isInt(t):
    try:
        _ = int(t)
        return True
    except:
        return False

mylist = ['-120$My life cycle$121$My daily routine','some$222$othr$text$42']
splitted = [[int(i) for i in p.split("$") if isInt(i) ] for p in mylist] 

print(splitted) # [[-120, 121], [222, 42]]

---

To get a flattened list no matter how many strings are in myList :

intlist = list(map(int,( d for d in '$'.join(myList).split("$") if isInt(d))))
print(intlist) # [-120, 121, 222, 42]

Answer 2

Updated version:

import re
myList = ['120$My life cycle 3$121$My daily routine 2']
myList = myList[0].split('$')
numbers = []
for i in range(0,len(myList),2):
        temp = re.findall(r'\d+', myList[i])[0]
        numbers.append(temp)
'''
.finall() returns list of all occurences of a pattern in a given string.
The pattern says map all digits in the string. If they are next to each
other count them as one element in final list. We use index 0 of the 
myList as thats the string we want to work with.
'''
results = list(map(int, numbers)) # this line performs an int() operation on each of the elements of numbers.
print(results)

Why not just use re ?

re is a library for regular expresions in python. They help you find patterns.

import re
myList = ['120$My life cycle 3$121$My daily routine 2']
numbers = re.findall(r'\d+$', myList[0]) 
'''
.finall() returns list of all occurences of a pattern in a given string.
The pattern says map all digits in the string. If they are next to each
other count them as one element in final list. We use index 0 of the 
myList as thats the string we want to work with.
'''
results = list(map(int, numbers)) # this line performs an int() operation on each of the elements of numbers. 
print(results)

Answer 3

First off we split string with '$' as separator. And then we just iterate through every other result from the new list, convert it into integer and append it to results.

myList = ['120$My life cycle 3$121$My daily routine 2']
myList = myList[0].split('$')
results = []
for i in range(0,len(myList),2):
    results.append(int(myList[i]))
print(results)
# [120, 121]

Answer 4

Do something like this?

a = ['100$My String 1A$290$My String 1B']
>>> for x in a:
...   [int(s) for s in x.split("$") if s.isdigit()]
...
[100, 290]