I have a location string with placeholders, used as '#'. Another string which are replacements for the placeholders. I want to replace them sequentially, (like format specifiers). What is the way to do it in Python?
location = '/tmp/#/dir1/#/some_dirx/dir/var/2/#/dir3'
replacements = 'xyz'
result = '/tmp/x/dir1/y/some_dirx/dir/var/2/z/dir3'
You should use the replace
method of a string as follows:
for replacement in replacements:
location = location.replace('#', replacement, 1)
It is important you use the third argument, count
, in order to replace that placeholder just once. Otherwise, it will replace every time you find your placeholder.
If your location string does not contains format specifiers ( {}
) you could do:
location = '/tmp/#/dir1/#/some_dirx/dir/var/2/#/dir3'
replacements='xyz'
print(location.replace("#", "{}").format(*replacements))
Output
/tmp/x/dir1/y/some_dirx/dir/var/2/z/dir3
As an alternative you could use the fact that repl in re.sub can be a function:
import re
from itertools import count
location = '/tmp/#/dir1/#/some_dirx/dir/var/2/#/dir3'
def repl(match, replacements='xyz', index=count()):
return replacements[next(index)]
print(re.sub('#', repl, location))
Output
/tmp/x/dir1/y/some_dirx/dir/var/2/z/dir3
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