I extract data using API and retrieve a list of servers and backups. Some servers have more than one backup. This is how I get list of all servers with backaup IDs.
bkplist = requests.get('https://heee.com/1.2/storage/backup')
bkplist_json = bkplist.json()
backup_list = bkplist.json()
backupl = backup_list['storages']['storage']
Json looks like this:
{
"storages": {
"storage": [
{
"access": "",
"created": "",
"license": ,
"origin": "01165",
"size": ,
"state": "",
"title": "",
"type": "backup",
"uuid": "01019",
"zone": ""
},
Firstly I create a dictionary to store this data:
backup = {}
for u in backup_list['storages']['storage']:
srvuuidorg = u['origin']
backup_uuid = u['uuid']
backup[srvuuidorg] = backup_uuid
But then I find out there is more than one value for every server. As dictionary can have just one value assigned to one key I wanted to use some hybrid of list and dictionary, but I just can't figure it out how to do this with this example.
Servers are nested in storages -> storage and I need to assign a couple of uuid which is backup ID to one origin which is server ID.
I know about collections module and with a simple example it is quite understandable, but I have a problem how to use this in my example with extracting data through API.
How extract origin and assign to this key other values stored in json uuid ?
What's more it is a massive amount of data so I cannot add every value manually.
You can do something like this.
from collections import defaultdict
backup = defaultdict(list)
for u in backup_list['storages']['storage']:
srvuuidorg = u['origin']
backup_uuid = u['uuid']
backup[srvuuidorg].append(backup_uuid)
Note that you can simplify your loop like this.
from collections import defaultdict
backup = defaultdict(list)
for u in backup_list['storages']['storage']:
backup[u['origin']].append(u['uuid'])
But this may be considering as less readable.
You could store uuid
list for origin
key.
I sugget the following 2 ways:
list
for first accessing origin
, and then appending to it:backup = {}
for u in backup_list['storages']['storage']:
srvuuidorg = u['origin']
backup_uuid = u['uuid']
if not backup.get(srvuuidorg):
backup[srvuuidorg] = []
backup[srvuuidorg].append(backup_uuid)
defaultdict
collection, which basically does the same for you under the hood:from collections import defaultdict
backup = defaultdict(list)
for u in backup_list['storages']['storage']:
srvuuidorg = u['origin']
backup_uuid = u['uuid']
backup[srvuuidorg].append(backup_uuid)
It seems to me that the last way is more elegant. If you need to store uuid
unique list you should use the saem approach with set
instead of list
.
A json allows to contain an array in a key:
var= {
"array": [
{"id": 1, "value": "one"},
{"id": 2, "value": "two"},
{"id": 3, "value": "three"}
]
}
print var
{'array': [{'id': 1, 'value': 'one'}, {'id': 2, 'value': 'two'}, {'id': 3, 'value': 'three'}]}
var["array"].append({"id": 4, "value": "new"})
print var
{'array': [{'id': 1, 'value': 'one'}, {'id': 2, 'value': 'two'}, {'id': 3, 'value': 'three'}, {'id': 4, 'value': 'new'}]}
You can use a list for multiple values.
dict = {"Greetings": ["hello", "hi"]}
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.