7z command in Python 3.6 subprocess.run() on Windows

Question

I have a python script that should run 7z.exe with the command: "x" and switch " -o" using subprocess.run(). The script is as follows:

import subprocess as sb


zipperpath = "C:\\Program Files\\7-zip\\7z.exe"
dirname ="C:\\Users\\ajain\\Desktop\\TempData"
archivename="UnprocessedData_v3.7z"
outputfilename="foo"

sb.run([zipperpath,"x",os.path.join(dirname,archivename)," -o",os.path.join(dirname,outputfilename)])

Output is: Although the return code is 0, the zip never gets unzipped.

Answer 1

Try with this :

import subprocess

# variable cmd is is your command line , like you put in your console 
cmd='7z.exe x UnprocessedData_v3.7z'

process = subprocess.Popen(cmd,shell=True,stdin=None,stdout=subprocess.PIPE,stderr=subprocess.PIPE)
# The output from your shell command in an array
result=process.stdout.readlines()
if len(result) >= 1:
    for line in result:
        print(line)