I have the following list:
fruits = [“apple”, “banana”, “grape”, “kiwi”, “banana”, “apple”, “apple”, “watermelon”, “kiwi”, “banana”, “apple”,]
Now I have to develop a function called count_the_fruits that would take as its arguments a list of fruits and a variable argument list called words. The function should use dictionary comprehension to create a dictionary of words (key) and their corresponding counts (value).
words = ["apple", "banana", "kiwi"]
Expect Output: {apple: 4, 'banana': 3, 'kiwi': 2}
Any help would be appreciated. Thanks!
I got you man, but try to ask your questions better.
words =[]
def count_the_fruits():
for fruit in fruits:
if words.count(fruit) >=1:
continue
words.append((fruit, fruits.count(fruit)))
print(words)
fruits = ["apple", "banana","grape", "kiwi", "banana", "apple", "apple", "watermelon", "kiwi", "banana", "apple"]
count_the_fruits()
How about?
def count_the_fruits(fruits, fruits_to_check_for):
# initialize variables:
fruit_count = {}
# iterate over each fruit in fruit list:
for fruit in fruits_to_check_for:
# count number of occurences:
number_of_fruits = len([x for x in fruits if x==fruit])
# add to dictionary:
fruit_count[fruit] = number_of_fruits
return fruit_count
if __name__ == '__main__':
fruits = ['apple', 'banana', 'grape', 'kiwi',
'banana', 'apple', 'apple', 'watermelon',
'kiwi', 'banana', 'apple',]
fruits_to_check_for = ['apple', 'banana']
result = count_the_fruits(fruits, fruits_to_check_for)
print(result)
The reason it is giving you only one count is because you are only searching for one. Try this:
fruits = ['apple', 'banana', 'grape', 'kiwi', 'banana', 'apple',
'apple', 'watermelon', 'kiwi', 'banana', 'apple']
words = ["apple", "banana", "kiwi"]
def count_the_fruits(fruits, words):
# This is a dict comprehension
counts = {word: fruits.count(word) for word in words}
return counts
print(count_the_fruits(fruits, words))
Output:
{'apple': 4, 'banana': 3, 'kiwi': 2}
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