Mirth Connect Channel destination sort JSON array of objects

Question

I need to sort an array of objects being sent into Mirth. Originally the sorting was done via XSLT (since the inbound data was XML), but with a change (outside of my control) the inbound data was changed to JSON. The original sorting was being done in a destination transformation which I have kept.

Inbound JSON example:

{
  "Id":"100001",
  "Set":
  {
    "unimportantdata1":null,
    "unimportantdata2":null,
    "unimportantdata3":"0001-01-01T00:00:00",
    "unimportantdata4":"0001-01-01T00:00:00",
    "ArrayToSort":[
      {
        "vt":"blah",
        "Num":"2",
        "desc":"dp",
        "Value":["1.1","1.2"],
        "Time":"2020-03-23T02:23:41",
        "blah": { "Name": { "LastName":"ob-ln","Firstname":"ob-fn","MiddleName":"ob-mi","Title":null}}
      },
      {
        "vt":"yadda",
        "Num":"1",
        "desc":"dp",
        "Value":["1.1","1.2"],
        "Time":"2020-03-23T02:23:41",
        "blah": { "Name":{"LastName":"ob-ln","Firstname":"ob-fn","MiddleName":"ob-mi","Title":null}}
      }
   ]}
}

I need the ArrayToSort ordered by the "Num" property ascending.

My questions are:

1. Is the best place to sort this in the destination channel transformer?
2. I'm guessing the way to go is via JavaScript, but I'm unsure how to proceed -- suggestions?

Thank you in advance

Answer 1

Turns out the solution is pretty simple.

In JavaScript, you just need to do the following:

msg['Set']['ArrayToSort'].sort(function(a,b){
    return a["Num"] - b["Num"];
});

logger.info(JSON.stringify(msg));

Answer 2

Sorting can be done, using Array.sort . And can update data

 let data = { Id: "100001", Set: { unimportantdata1: null, unimportantdata2: null, unimportantdata3: "0001-01-01T00:00:00", unimportantdata4: "0001-01-01T00:00:00", ArrayToSort: [ { vt: "blah", Num: "2", desc: "dp", Value: ["1.1", "1.2"], Time: "2020-03-23T02:23:41", blah: { Name: { LastName: "ob-ln", Firstname: "ob-fn", MiddleName: "ob-mi", Title: null } } }, { vt: "yadda", Num: "1", desc: "dp", Value: ["1.1", "1.2"], Time: "2020-03-23T02:23:41", blah: { Name: { LastName: "ob-ln", Firstname: "ob-fn", MiddleName: "ob-mi", Title: null } } } ] } }; data.Set.ArrayToSort = data.Set.ArrayToSort.sort((x, y) => x.Num - y.Num); console.log(JSON.stringify(data, null, 2));