C++ code
fs::path pathToShow("C:\Windows\system.ini");
cout << "exists() = " << fs::exists(pathToShow) << "\n"
<< "root_name() = " << pathToShow.root_name() << "\n"
<< "root_path() = " << pathToShow.root_path() << "\n"
<< "relative_path() = " << pathToShow.relative_path() << "\n"
<< "parent_path() = " << pathToShow.parent_path() << "\n"
<< "filename() = " << pathToShow.filename() << "\n"
<< "stem() = " << pathToShow.stem() << "\n"
<< "extension() = " << pathToShow.extension() << "\n";
Taken from an example from https://www.codingame.com
Output
exists() = 0
root_name() = "C:"
root_path() = "C:"
relative_path() = "Windowssystem.ini"
parent_path() = "C:"
filename() = "Windowssystem.ini"
stem() = "Windowssystem"
extension() = ".ini"
Press any key to continue . . .
Does Visual Studio have an compiler/linker option to threat the '\' symbol as
\\
when outputing with cout or printf? Or is there another simple way without making an own function to manipulate the string (without too much hazzle)?
Not a compiler option, but a language feature: use a raw string literal . Should work on all compilers.
fs::path pathToShow(R"(C:\Windows\system.ini)");
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