I want to write a bash script and I need to get the filenames in a directory and I've done this:
list=`ls -p -m -1 $dir | grep -v /`
list=`echo $list | tr ' ' ','`
IFS=',' read -ra list_array <<< $list
If no file with whitespaces in the current directory exists, then the variable list_array
holds the correct space-seperated array of filenames:
$ echo "${list_array[*]}"
a a.rar a.tar a.zip blah blah blah
But that wouldn't work correctly in situations where there exists some files with whitespaces in their names.To mitigate this, I changed that as follows:
list=`ls -p -m $dir | grep -v /` #This doesn't work in for filenames without whitespace
IFS=',' read -ra list_array <<< $list
But now list_array
only holds the name of the first file.
Any help is greatly appreciated.
You can use newlines as IFS.
IFS=$'\n'
list_array=(`ls -p -m -1 . | grep -v /`)
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