I need to display a string on multiple lines at a set interval. For example
if the string is ABCDEFGHI
and the interval is 3 then it needs to print
ABC
DEF
GHI
Right now, I have a function with 2 inputs
def show_string(chars: str, interval: int) -> str:
...
Please help!
Use list comprehension:
def show_string(chars: str, interval: int):
[print(chars[obj:obj+interval]) for obj in range(0, len(chars), interval)]
You can use the inbuilt function wrap
from the textwrap
module
from textwrap import wrap
def show_string(chars: str, interval: int):
words = wrap(chars, interval)
# Print the words
for word in words:
print(word)
# Or return the list of words
return words # contains ['ABC', 'DEF', 'GHI']
see this simple code:
test="abcdefghi"
x=[]
while len(test) != 0:
x.append(test[:3])
test=test[3:]
print(x)
print(''.join(x))
You can try this, I have used while loop:
def foo(chars,intervals):
i = 0
while i < len(chars):
print(chars[i:i+3])
i+=3
foo("ABCDEFGHI",3)
You can try this probably a more pythonic way than the previous answer, however this function only returns None, because it just prints the values
def show_string(chars: str, interval: int) -> None:
[print(chars[i:i+interval]) for i in range(0, len(chars), interval)]
if you were to return a list of strings you cans simply rewrite:
def show_string(chars: str, interval: int)-> list[str]:
return [chars[i:i+interval] for i in range(0, len(chars), interval)]
I think something like this would help.
def show_string(chars: str, interval: int):
for i in range(0, len(chars), interval):
print(chars[i:i+interval])
from itertools import zip_longest
def show_string(chars, interval):
out_string = [''.join(lis) for lis in group(interval, chars, '')]
for a in out_string:
print(a)
# Group function using zip_longest to split
def group(n, iterable, fillvalue=None):
args = [iter(iterable)] * n
return zip_longest(fillvalue=fillvalue, *args)
show_string("ABCDEFGHI", 3)
Output:
ABC
DEF
GHI
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