Sort a list alphabetically first and then numerically?

Question

How can I sort a list of strings alphabetically first and then numerically in Python?

Eg:

Given list: li = ['4', '1', '3', '9', 'Z', 'P', 'V', 'A']

I want the following output after sorting:

sorted_list = ['A', 'P', 'V', 'Z', '1', '3', '4', '9']

Answer 1

sorted(sorted_list, key=lambda x: (x.isnumeric(),int(x) if x.isnumeric() else x))

this sorts also by value of the integer

Answer 2

You can try this. The desired output can achieved by using str.isdigit

sorted(l,key=lambda x:(x.isdigit(),x))
# ['A', 'P', 'V', 'Z', '1', '3', '4', '9']

NOTE: This solution doesn't handle digits more than one. Please take a look at @Martin's answer.

Answer 3

list1 = ['4', '1', '3', '9', 'Z', 'P', 'V', 'A']
number = []
alphabet = []
for l in list1:
    if l.isnumeric():
        number.append(l)
    else:
        alphabet.append(l)

number = sorted(number)
alphabet = sorted(alphabet)
list1 = alphabet + number
print(list1)

Answer 4

In case you want it to take in consideration negative numbers, decimals and lower-case letters:

li = ['A', 'b', '-400', '1.3', '10', '42', 'V', 'z']

threshold = abs(min(float(x) for x in li if not x.isalpha())) +  ord('z') + 1
sorted_list = sorted(li,
                     key=lambda x: ord(x) if x.isalpha() else threshold + float(x))

sorted_list :

['A', 'V', 'b', 'z', '-400', '1.3', '10', '42']