Here I need to compare the elements present in a Set with the elements in an array.
`System.out.println("Enter Student's Article");
sentence=sc.nextLine();
lowerCase(sentence);
String [] array=sentence.split("[ ,;:.?!]+");
System.out.println("Number of words "+array.length);
Set <String> set=new HashSet<>(Arrays.asList(array));
//System.out.println(set.size());
for(String str:set){
count=0;
for(int j=0;j<array.length;j++){
if(str==array[j])
count++;
System.out.println(count);
}
System.out.println(str+":"+count);
}
}`
The logic behind my code is: I received an input sentence and I converted it into lowercase. Then I split each word based on some characters as mentioned in the code and store each splitted word to array. Now I convert it into a set. Now I need to count the frequency of each element in the set with repsect to the array.
For example If I give input as "hi hi hi hello" I would get Number of words 4 hi:3 hello:1
So please help me to solve this.
Try the code below and compare the changes with your original code
Scanner sc=new Scanner(System.in);
String sentence=sc.nextLine();
sentence.toLowerCase();
String [] array=sentence.split("[ ,;:.?!]+");
System.out.println("Number of words "+array.length);
Set <String> set=new HashSet<>(Arrays.asList(array));
//System.out.println(set.size());
for(String str:set){
int count=0;
for(int j=0;j<array.length;j++){
if(str.equals(array[j]))
count++;
//System.out.println(count);
}
System.out.println(str+":"+count);
}
Use the below code count the frequency of each element.
Map<String , Integer> dictionary=new HashMap<String,Integer>();
String myWords = "soon hi also soon job mother job also soon later";
myWords = myWords.toLowerCase();
String[] array=myWords.split("\\s+");
for(String s:array){
if(dictionary.containsKey(s))
dictionary.put(s, dictionary.get(s)+1);
else
dictionary.put(s, 1);
}
System.out.println("Number of words "+myWords.length());
for (String key : dictionary.keySet()) {
System.out.print(key +":"+ dictionary.get(key));
}
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