Get the word from sentence that match to an array PHP

Question

Currently I have this variable in php

   @if(count($label_types) > 0)
   @foreach ($label_types as $label_type)
      @if($label_type)
        {{ $label_type->fldLabelTypeName }}
      @endif
   @endforeach
   @endif

Which contains the following rows

Waterproof (This is waterproof)

Glossy

Normal

Now since waterproof has the (This is waterproof) on the records

Now I want to only return the words that matches with these keywords

waterproof , glossy , normal

whether they are uppercases , lowercases

For example if the case is: waterproofss with double s

the return would be waterproof

Answer 1

You can solve your problem by using regex. First, you need to map your cases on string-like key waterprofs|waterproffs|waterproffss and value Waterproof for these cases. Your mapped key will work as a pattern in a regex. preg_match will check your pattern in your string. if the pattern matched, then it will return its value which one you defined in your map.

function getLabel(string $string)
{
    // You own custom map using regex, key-value pair,
    $matchersMap = [
        'waterproofs|waterproof' => 'Waterproof',
        'glossies|glossy' => 'Glossy',
        'normal' => 'Normal'
    ];

    $result = -1;

    foreach($matchersMap as $matchesKey => $replaceValue) {
        if (preg_match("/$matchesKey/", strtolower($string))) {
            $result = $replaceValue;
            break;
        }
    }

    return $result;
}

var_dump(getLabel("waterproof has the (This is waterproof)")); //Waterproof 

Hopefully, you will get a minimum idea of how you will show your desired value by using regex.