split by regex except

Question

import re
digit_count=0
number_count = 0
numbers = []
count=0

with open ("letters_and_numbers.txt") as f:
  for line in f.readlines():
    sub_strs = line.rstrip().split("-")
    file_words = re.split(r"[a-zA-Z\W]",line.rstrip())
    for word in file_words:
      if word.isdigit():
        digit_count += len(word)
        number_count += 1
        numbers.append(word)        
        foundNeg=False
        for i in range(1, len(sub_strs)):
          if str(sub_strs).startswith(word):
            foundNeg == True
            count-=int(word)
          else:
            foundNeg==False
            count+=int(word)

print "digits:",digit_count
print "amount of numbers:",number_count
print "numbers:",numbers
print "total:",count

I am trying to get the above program to work but it only can if i can split by regex whitespaces except negative signs.How do I fix it???

NEVER MIND I FIGURED IT OUT

Answer 1

Here is my answer.It is the code I used and it worked even when there were no spaces between numbers and letters.

import re
digit_count=0
number_count = 0
numbers = []
count=0

with open ("letters_and_numbers.txt") as f:
  for line in f.readlines():
    sub_strs = line.rstrip().split("-")
    for i in range(0, len(sub_strs)):
      file_words = re.split(r"[a-zA-Z\W]",sub_strs[i])
      for word in file_words:
        if word.isdigit():
          digit_count += len(word)
          number_count += 1
          if i >=1 and sub_strs[i].startswith(word):
            count-=int(word)
            digit_count+=1
            numbers.append("-")
            numbers.append(word)
          else:
            count+=int(word)
            numbers.append(word)

print "digits:",digit_count
print "amount of numbers:",number_count
print "numbers:",numbers
print "total:",count