Formatting hex to be printed with 2 digits?

Question

The built-in function hex() in python returns me a number in the form 0xf or 0x0 but i want them as 0x00. I found this on the python docs but dont really know how to interpret it.

Thanks

Answer 1

You can use string formatting for this purpose:

>>> "0x{:02x}".format(13)
'0x0d'

More detailed examples here:

How can I format an integer to a two digit hex?

Answer 2

In python3, use this f string format:

f"0x{variable:02x}"

For maximum python2/3 compatibility, use .format() :

"0x{:02x}".format(variable)

Answer 3

Here is how:

print('0x'+hex(4)[2:].zfill(2))

Output:

'0x04'

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Breaking it down:

• hex(4) , as you know, will return '0x4' . hex(4)[2:] means to get all the characters in the string after the second one, so it will be '4' .

• The str.zfill() method will pad a string with the specified number of zeros we pass into the brackets, so hex(4)[2:].zfill(2) will be '04' .

• Finally, be put the first two characters ( '0x' ) we sliced off in the beginning back to the beginning of the string.