How to use string formatting with specific nubmer of digits on hex Ascii

Question

In Python 2.7, I want to convert hex ascii number to itself using string formating with specific number of digits

Example:

hexNumber='9'
print '%02x' % (hexNumber)

Output:

09

Answer 1

You have a string , just zero-fill it to the desired width usingstr.zfill() :

hexNumber.zfill(2)

The %x formatter is for integers only.

Demo:

>>> hexNumber = '9'
>>> hexNumber.zfill(2)
'09'

Answer 2

You can also make use of Python's format command for string formatting. This allows you to specify a fill character, in this case 0 and a width as follows:

print "{:0>2s}".format('9')

This would display:

09

Answer 3

print(("{0:05X}".format(int("1C", 16))))

0001C

print(("{0:05X}".format(0x1C)))

0001C