I have the following array
var array = [["ABC", "123"], ["DEF", "456"];
How can I get "123", if I look for "ABC? I tried
array["ABC"][1] //Want Output: 123
array["DEF"][1] //Want Output: 456
You can use Array#find
.
var array = [["ABC", "123"], ["DEF", "456"]]; let abc = array.find(x=>x[0]==="ABC"); console.log(abc?.[1]); let def = array.find(x=>x[0]==="DEF"); console.log(def?.[1]); let nothing = array.find(x=>x[0]==="NOTHING"); console.log(nothing?.[1]);
However, using an object or Map
is much better suited to this purpose. You can convert your array to an object using Object.fromEntries
.
var array = [["ABC", "123"], ["DEF", "456"]]; const obj = Object.fromEntries(array); console.log(obj.ABC); console.log(obj['DEF']);
You can pass the array to the Map
constructor as well. Map
s are better if you always want to retain insertion order.
var array = [["ABC", "123"], ["DEF", "456"]]; const map = new Map(array); console.log(map.get("ABC")); console.log(map.get("DEF"));
You can use find
to locate the item with the value at index 0
. If you found, return the value at index 1
.
const findByFirstValue = (arr, val) => ((res) => res? res[1]: null)(arr.find(v => v[0] === val)) console.log(findByFirstValue([["ABC", "123"], ["DEF", "456"]], 'ABC'))
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You can use map
const array = [["ABC", "123"], ["DEF", "456"]]; const newMap = new Map(); array.map(item=>{ newMap[item[0]] = item; }) console.log(newMap['ABC'][1]);
what you are trying to do is impossible using array, you are not allowed to use:
array["ABC"]
since array's indexing is number based, you need to use objects in order to get what you want:
var array = {"ABC": ["123", "789"], "DEF": ["456", "323"]};
now you are able to select them as you want:
array['ABC'][1] // 123
you can use index to get a value from array in
//first level
// array[0] =>["ABC", "123"]
// array[1] => ["DEF", "456"]
//second level
// array[0][0]=> "ABC"
// array[0][1]=> "123"
also you can use methods like map or foreach
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