Passing arguments to a thread in python

Question

I keep getting the error

Traceback (most recent call last):
File "main.py", line 37, in <module>
controller = threading.Thread(target=get_controller(), args=(q,))
TypeError: get_controller() missing 1 required positional argument: 'q'

Whenever I try to create a thread in python. Here's the code I'm using

def get_controller(q):
    q.put(get_gamepad())
return

q = queue.Queue()
events = []
controller = threading.Thread(target=get_controller(), args=(q,))

I know it's not the common error of forgetting to add a "," after the first argument in "args", but I'm not sure what else it could be.

Answer 1

When you pass the target, you should pass the pointer to the function you want. Instead, what you are doing is calling the function, which is not your desired effect. Try this instead:

controller = threading.Thread(target=get_controller, args=(q,))

Answer 2

You should not use () in target=

threading.Thread(target=get_controller, args=(q,))