how to sort a list based on a specific keywords in the string

Question

i have this list below

my_list = ['STNNC-A11-SD03', 'STNNC-BDD-SD01', 'STNNC-BDD-SD04', 'STNNC-BDB-SD02']

i tried below method and this is what it returned which is expected since its sorting from left to right:

my_list.sort()
print(my_list)

['STNNC-A11-SD03', 'STNNC-BDB-SD02', 'STNNC-BDD-SD01', 'STNNC-BDD-SD04']

but below is the output i am looking for

['STNNC-BDD-SD01', 'STNNC-BDB-SD02', 'STNNC-A11-SD03', 'STNNC-BDD-SD04']

is there anyway that i can sort the list based the last numerical section?

Thanks so much.

Answer 1

You can use sorted() and extrcat the number from string use the number as key in sorted

res = sorted(my_list, key=lambda x: int(x.split('-SD')[-1]))
print(res)

Output:

['STNNC-BDD-SD01', 'STNNC-BDB-SD02', 'STNNC-A11-SD03', 'STNNC-BDD-SD04']

Answer 2

If you just want to sort based on the third component of each string, you can use:

my_list.sort(key=lambda s: s.split("-")[2])

This produces:

['STNNC-BDD-SD01', 'STNNC-BDB-SD02', 'STNNC-A11-SD03', 'STNNC-BDD-SD04']

Answer 3

#you can try this, I hope you will get you solution.

my_list = ['STNNC-A11-SD03', 'STNNC-BDD-SD01', 'STNNC-BDD-SD04', 'STNNC-BDB-SD02']

base_list = []
for i in my_list:
    base_list.append(int(i[-2:]))

zipped_lists = zip(base_list, my_list)

sorted_zipped_lists = sorted(zipped_lists)

sorted_list = [element for _, element in sorted_zipped_lists]

print(sorted_list)