Trying to count the total number of wins and total times a horse finished in the top 6 and GROUP
by the order of favouritism in a horse racing market.
I am referencing this answer since it is looking for a similar outcome Count the occurrences of DISTINCT values
I have tried this expression but when executed, it returns the same number in both case columns
ie;
SPFav WinsByFavouritism PlaceByFavouritism
1 4143 4143
2 3963 3963
3 3853 3853
This is the code I am running - what is causing this?
SELECT SPFav,
COUNT(CASE WHEN FinishingPosition = 1 THEN 1 ELSE 0 END) as WinsByFavouritism,
COUNT(CASE WHEN FinishingPosition <= 6 THEN 1 ELSE 0 END) as PlaceByFavouritism
FROM [NRaceHistory].[dbo].[EachWayBetting]
GROUP BY SPFav
ORDER BY SPFav ;
Working with the first comment this would give the following possible solution.
Sample data
create table EachWayBetting
(
SPFav int,
FinishingPosition int
);
insert into EachWayBetting (SPFav, FinishingPosition) values
(1, 1),
(1, 2),
(1, 2),
(1, 9),
(2, 7),
(2, 8),
(2, 2),
(2, 1);
Solution
SELECT SPFav,
COUNT(CASE WHEN FinishingPosition = 1 THEN 1 END) as WinsByFavouritism,
COUNT(CASE WHEN FinishingPosition <= 6 THEN 1 END) as PlaceByFavouritism
FROM EachWayBetting
GROUP BY SPFav
ORDER BY SPFav
Result
SPFav WinsByFavouritism PlaceByFavouritism
----- ----------------- ------------------
1 1 3
2 1 2
I believe you should replace COUNT in your query with SUM. ie it should be:
SELECT SPFav,
SUM(CASE WHEN FinishingPosition = 1 THEN 1 ELSE 0 END) as WinsByFavouritism,
SUM(CASE WHEN FinishingPosition <= 6 THEN 1 ELSE 0 END) as PlaceByFavouritism
FROM [NRaceHistory].[dbo].[EachWayBetting]
GROUP BY SPFav
ORDER BY SPFav;
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