how to split string from the end after certain occurances of character

Question

how to split the below string after 2nd occurrence of '/' from the end:

/u01/dbms/orcl/product/11.2.0.4/db_home

Expected output is:

/u01/dbms/orcl/product/

Thanks.

Answer 1

Do not use split , use rsplit instead. It's much simpler and faster.

s = '/u01/dbms/orcl/product/11.2.0.4/db_home'
result = s.rsplit('/', 2)[0] + '/'

Answer 2

string = "/u01/dbms/orcl/product/11.2.0.4/db_home"
split_string = string.split('/')
expected_output = "/".join(split_string[:-2]) + "/"

You're also free to change "-2" to minus whatever amount of filenames you need clipped.

Answer 3

If you can parse it as a filepath, I recommend pathlib , try:

from pathlib import Path

p = Path('/u01/dbms/orcl/product/11.2.0.4/db_hom')

p.parent.parent # Returns object containg path /u01/dbms/orc1/product/ 

Answer 4

input='/u01/dbms/orcl/product/11.2.0.4/db_home'
output = '/'.join(str(word) for word in input.split('/')[:-2])+'/'